Consider the following reactions :
\( NaCl{\rm{ }} + {\rm{ }}{K_2}C{r_2}{O_7} + \mathop {{H_2}S{O_4}}\limits_{(conc.)} \)\( \to \) (A) + side products
(A) + NaOH \( \to \) (B) + Side products
\( \left( B \right){\rm{ }} + \mathop {{H_2}S{O_4}}\limits_{(dilute)} + {\rm{ }}{H_2}{O_2} \) \( \to \) (C) + Side products
The sum of the total number of atoms in one molecule each of (A) and (B) and (C) is
\( NaCl{\rm{ }} + {\rm{ }}{K_2}C{r_2}{O_7} + \mathop {{H_2}S{O_4}}\limits_{(conc.)} \)\( \to \) (A) + side products
(A) + NaOH \( \to \) (B) + Side products
\( \left( B \right){\rm{ }} + \mathop {{H_2}S{O_4}}\limits_{(dilute)} + {\rm{ }}{H_2}{O_2} \) \( \to \) (C) + Side products
The sum of the total number of atoms in one molecule each of (A) and (B) and (C) is
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Correct Answer: 18
Solution and Explanation
Step 2: CrO2Cl2 + 4NaOH gives Na2CrO4 (B), yellow, + 2NaCl + 2H2O. Atoms: 2 + 1 + 4 = 7.
Step 3: Na2CrO4 + dil. H2SO4 + H2O2 gives the blue peroxide CrO(O2)2 = CrO5 (C). Atoms: 1 + 5 = 6.
Step 4: Total \(=5+7+6=18\).
Answer: 18
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