Consider the following reactions:
\[
K_2Cr_2O_7 + 2 KOH \xrightarrow{ \text{heat} } [A]
\]
\[
[A] + H_2SO_4 \xrightarrow{} [B] + K_2SO_4
\]
The products [A] and [B], respectively are:
Show Hint
- \( K_2Cr(OH)_6 \) and \( Cr_2O_3 \)
- \( K_2CrO_4 \) and \( Cr_2O_3 \)
- \( K_2CrO_4 \) and \( K_2Cr_2O_7 \)
- \( K_2CrO_4 \) and \( CrO \)
The Correct Option is C
Approach Solution - 1
To solve this question, we need to analyze the given chemical reactions step-by-step and determine the products [A] and [B]. Let's go through the reactions:
- The first reaction is:
\(K_2Cr_2O_7 + 2 KOH \xrightarrow{ \text{heat} } [A]\)
In this reaction, potassium dichromate \(K_2Cr_2O_7\) reacts with potassium hydroxide \(KOH\) under heat. The product formed, [A], is potassium chromate \(K_2CrO_4\). This involves a change from the dichromate anion to the chromate anion.
- The second reaction is:
\([A] + H_2SO_4 \xrightarrow{} [B] + K_2SO_4\)
In this reaction, [A] (which we identified as \(K_2CrO_4\)) reacts with sulfuric acid \(H_2SO_4\). This reaction converts the chromate ion back to the dichromate ion. The product [B] is potassium dichromate, \(K_2Cr_2O_7\), and potassium sulfate \(K_2SO_4\) is also formed.
Therefore, the correct products for the reactions are:
- [A]: \(K_2CrO_4\)
- [B]: \(K_2Cr_2O_7\)
Given these deductions, the correctly matched products according to the options provided are:
\(K_2CrO_4\) and \(K_2Cr_2O_7\)
Approach Solution -2
- In the second reaction, \( K_2CrO_4 \) reacts with sulfuric acid (H2SO4), resulting in chromium trioxide \( Cr_2O_3 \) as the product [B]. Thus, the correct products are [A] = \( K_2CrO_4 \) and [B] = \( K_2Cr_2O_7 \).
Top JEE Main Chemistry Questions
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- At equilibrium the concentrations of and in a sealed vessel at . What will be for the reaction
- Find out the major products from the following reactions
Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
- The correct order of atomic radii is:
Top JEE Main Reactions of Chromium Compounds Questions
- Identify the products [A] and [B] respectively in the following reaction:
![Identify the products [A] and [B] respectively in the following reaction:](https://images.collegedunia.com/public/qa/images/content/2025_03_17/Screenshot_677f6f511742225539486.png)
- Correct statements from the following are:
A. Potassium dichromate is an oxidising agent and it oxidises FeSO₄ to Fe₂(SO₄)₃ in acidic medium.
B. Sodium dichromate can be used as primary standard in volumetric estimation.
C. CrO₄²⁻ and Cr₂O₇²⁻ are interconvertible in aqueous solution by varying the pH of the solution.
D. Cr-O-Cr bond angle in Cr₂O₇²⁻ is 126°.
Choose the correct answer: Consider the following molecules/species:
The correct order of carbon - oxygen double bond length is :
Top JEE Main Questions
- Two masses $m$ and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$. The rod is suspended by a thin wire of torsional constant $k$ at the centre of mass of the rod-mass system(see figure). Because of torsional constant $k$, the restoring torque is $\tau =k\theta$ for angular displacement $\theta$. If the rod is rota ted by $\theta_0$ and released, the tension in it when it passes through its mean position will be:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,