Step 1: Analyze the circuit without propagation delays.
The circuit includes an AND gate and a NOT gate. The input to the AND gate is \( X \) and the output of the NOT gate (i.e., \( \neg X \)).
The AND gate has two inputs: \( X \) and \( \neg X \).
For any value of \( X \):
\[
Y = X \land \neg X.
\]
Since \( X \land \neg X = 0 \) for all values of \( X \), the output \( Y \) is always logic Zero without propagation delays.
Thus, Option (1) is TRUE, and Option (2) is FALSE.
Step 2: Analyze the circuit with propagation delays.
When \( X \) transitions from logic Zero to logic One:
1. The NOT gate takes some time to invert the signal from \( X \) to \( \neg X \).
2. During this propagation delay, both inputs of the AND gate could temporarily be logic One.
This causes a transient logic One at \( Y \).
Thus, Option (3) is TRUE.
When \( X \) transitions from logic One to logic Zero, the NOT gate's propagation delay does not lead to a transient logic Zero at \( Y \), because the AND gate will have at least one input at logic Zero.
Thus, Option (4) is FALSE.
Final Answer:
\[
\boxed{\text{(1) and (3)}}
\]