Consider the above reaction. The percentage yield of amide product is __________. (Round off to the Nearest Integer).
(Given : Atomic mass : C : 12.0 u, H : 1.0 u, N : 14.0 u, O : 16.0 u, Cl : 35.5 u)
Consider the above reaction. The percentage yield of amide product is __________. (Round off to the Nearest Integer).
(Given : Atomic mass : C : 12.0 u, H : 1.0 u, N : 14.0 u, O : 16.0 u, Cl : 35.5 u)
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Correct Answer: 77
Solution and Explanation
Molar masses: C6H5COCl = 7(12) + 5(1) + 16 + 35.5 = 140.5 g/mol; (C6H5)2NH = 12(12) + 11 + 14 = 169 g/mol; amide C19H15NO = 228 + 15 + 14 + 16 = 273 g/mol.
Moles of benzoyl chloride = 0.140/140.5 = 9.96 × 10-4; moles of diphenylamine = 0.388/169 = 2.30 × 10-3.
Benzoyl chloride is the limiting reagent (1 : 1 reaction).
Theoretical mass of amide = 9.96 × 10-4 × 273 = 0.272 g.
% yield = (0.210/0.272) × 100 = 77.2 ≈ 77.
Answer: 77
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