The Lagrangian \( L \) is given by the difference between the kinetic and potential energies of the system.
- The kinetic energy consists of:
1. The translational kinetic energy of the mass \( M + m \) moving horizontally with velocity \( \dot{x} \).
2. The rotational kinetic energy of the rod, which involves the angular velocity \( \dot{\theta} \) and the moment of inertia of the rod.
- The potential energy consists of:
1. The spring potential energy, \( \frac{1}{2} k x^2 \).
2. The gravitational potential energy, \( mg \cos \theta \), where \( g \) is the gravitational constant.
Additionally, there is an applied horizontal force \( F \) at point Q, and the Lagrangian includes the work done by this force, \( F b \sin \theta \).
Thus, the Lagrangian for this system is given by:
\[
L = \frac{1}{2} (M + m) \dot{x}^2 + \frac{1}{2} m b \dot{x} \cos \theta + \frac{1}{6} m b^2 \dot{\theta}^2 - \frac{1}{2} k x^2 + mg \cos \theta + F b \sin \theta
\]
Therefore, the correct answer is (B).