Question:
Consider a equation P(x)= ax2 + bx + c =0. If a,b,c ∈ A, were A = {1, 2, 3, 4, 5, 6} . Then the probability that P(x) has real and distinct roots?
Consider a equation P(x)= ax2 + bx + c =0. If a,b,c ∈ A, were A = {1, 2, 3, 4, 5, 6} . Then the probability that P(x) has real and distinct roots?
Updated On: Feb 25, 2026
- \(\frac{1}{4}\)
- \(\frac{1}{16}\)
- \(\frac{25}{108}\)
- \(\frac{19}{108}\)
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The Correct Option is D
Solution and Explanation
The Correct answer is option is (D) : \(\frac{19}{108}\)
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