Consider a carrier signal which is amplitude modulated by a single-tone sinusoidal message signal with a modulation index of 50%. If the carrier and one of the sidebands are suppressed in the modulated signal, the percentage of power saved (rounded off to one decimal place) is .
The modulation index \( m \) is 50%, or \( m = 0.5 \). In amplitude modulation, the total power \( P_t \) is given by: \[ P_t = P_c \left( 1 + \frac{m^2}{2} \right) \] where \( P_c \) is the carrier power. When one of the sidebands is suppressed, the power saving occurs due to the absence of one sideband. The percentage of power saved is: \[ \text{Power saved} = \frac{m^2}{1 + \frac{m^2}{2}} \times 100 \] Substituting \( m = 0.5 \): \[ \text{Power saved} = \frac{(0.5)^2}{1 + \frac{(0.5)^2}{2}} \times 100 \approx 94.2\% \] Thus, the percentage of power saved is \( 94.2 \% \).
Let \( f(t) \) and \( g(t) \) represent continuous-time real-valued signals. If \( h(t) \) denotes the cross-correlation between \( f(t) \) and \( g(-t) \), its continuous-time Fourier transform \( H(j\omega) \) equals: Note: \( F(j\omega) \) and \( G(j\omega) \) denote the continuous-time Fourier transforms of \( f(t) \) and \( g(t) \), respectively.
In the circuit shown in the figure, the transistors M1 and M2 are operating in saturation. The channel length modulation coefficients of both the transistors are non-zero. The transconductance of the MOSFETs M1 and M2 are \( g_{m1} \) and \( g_{m2} \), respectively, and the internal resistance of the MOSFETs M1 and M2 are \( r_{o1} \) and \( r_{o2} \), respectively. Ignoring the body effect, the ac small signal voltage gain \( \frac{\partial V_{\text{out}}}{\partial V_{\text{in}}} \) of the circuit is 
A JK flip-flop has inputs $J = 1$ and $K = 1$.
The clock input is applied as shown. Find the output clock cycles per second (output frequency).

f(w, x, y, z) =\( \Sigma\) (0, 2, 5, 7, 8, 10, 13, 14, 15)
Find the correct simplified expression.
For the non-inverting amplifier shown in the figure, the input voltage is 1 V. The feedback network consists of 2 k$\Omega$ and 1 k$\Omega$ resistors as shown.
If the switch is open, $V_o = x$.
If the switch is closed, $V_o = ____ x$.

Consider the system described by the difference equation
\[ y(n) = \frac{5}{6}y(n-1) - \frac{1}{6}(4-n) + x(n). \] Determine whether the system is linear and time-invariant (LTI).