For Lassaigne’s test:
• Organic compounds must contain nitrogen or halogens for detection.
• Both nitrogen and halogen must be part of the same compound to test positive for both.
CH3NH2.HCl
NH2OH .HCl
NH4Cl
N2H4 . HCl
1. Lassaigne’s Test: This test detects nitrogen, sulfur, and halogens in organic compounds.
- The compound is fused with sodium, converting nitrogen into NaCN and halogen into NaX (\(X = \text{Cl, Br, I}\)).
2. Compound Analysis:
\(\text{N}_2\text{H}_4\cdot\text{HCl}\): Contains nitrogen but no halogen.
\(\text{CH}_3\text{NH}_2\cdot\text{HCl}\): Contains both nitrogen (from the \(-\text{NH}_2\) group) and halogen (\(\text{Cl}\) from \(\text{HCl}\)).
\(\text{NH}_4\text{Cl}\): Contains nitrogen and halogen but is not an organic compound.
\(\text{NH}_2\text{OH}\cdot\text{HCl}\): Contains nitrogen and halogen but does not form the required products in Lassaigne’s test.
3. Conclusion: Only \(\text{CH}_3\text{NH}_2\cdot\text{HCl}\) gives a positive Lassaigne’s test for both nitrogen and halogen.
Final Answer: (2) \(\text{CH}_3\text{NH}_2\cdot\text{HCl}\).
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are

CH$_3$–Br $\xrightarrow{\text{CH$_3$OH/Nu}}$ CH$_3$OH
Correct order of rate of this reaction for given nucleophile:

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)