Compare boiling point of given solutions:
(i) \( 10^{-4} \, \text{M NaCl} \)>(ii) \( 10^{-3} \, \text{M NaCl} \)>(iii) \( 10^{-2} \, \text{M NaCl} \)>(iv) \( 10^{-4} \, \text{M urea} \)
(iii) \( 10^{-2} \, \text{M NaCl} \)>(ii) \( 10^{-3} \, \text{M NaCl} \)>(i) \( 10^{-4} \, \text{M NaCl} \)>(iv) \( 10^{-4} \, \text{M urea} \)
(ii) \( 10^{-3} \, \text{M NaCl} \)>(i) \( 10^{-4} \, \text{M NaCl} \)>(iii) \( 10^{-2} \, \text{M NaCl} \)>(iv) \( 10^{-4} \, \text{M urea} \)
(iii) \( 10^{-2} \, \text{M NaCl} \)>(ii) \( 10^{-3} \, \text{M NaCl} \)>(i) \( 10^{-4} \, \text{M NaCl} \)>(iv) \( 10^{-4} \, \text{M urea} \)

In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 