The correct answer is C:1113 The expression can be rewritten as a sum of terms involving various coefficients: \([ (1+x^2)^4 \cdot (1+x^3)^7 \cdot (1+x^4)^{12} ]\) \( = (4C_0 + 4C_1 x^2 + 4C_2 x^4 + 4C_3 x^6 + 4C_4 x^8) \cdot (7C_0 + 7C_1 x^3 + 7C_2 x^6 + 7C_3 x^9 + \ldots + 7C_7 x^{21}) ]\) \([ \cdot (12C_0 + 12C_1 x^4 + 12C_2 x^8 + \ldots + 12C_{12} x^{48}) ]\) The objective is to find the term that contains \(( x^{11} )\) which corresponds to a power of ( x ) equal to 11. This can be achieved by selecting appropriate combinations of coefficients from each part\(= (4C_0 \cdot 7C_1 \cdot 12C_2) + (4C_1 \cdot 7C_3 \cdot 12C_0) + (4C_2 \cdot 7C_1 \cdot 12C_1) + (4C_4 \cdot 7C_1 \cdot 1) ]\) Calculating these products of coefficients: \( = [(1 \cdot 7 \cdot 66) + (4 \cdot 35 \cdot 1) + (6 \cdot 7 \cdot 12) + (1 \cdot 7) = 462 + 140 + 504 + 7 = 1113 ]\) So, the coefficient of \(( x^{11} )\) in the given expression is 1113. In a more natural language: The expression is composed of three parts, each raised to a certain power, and it's required to determine the coefficient of \(( x^{11} )\) in the expanded form. This involves selecting appropriate coefficients from each part. After calculating the necessary products of coefficients, the coefficient of \(( x^{11} )\)is found to be 1113.
The binomial theorem formula is used in the expansion of any power of a binomial in the form of a series. The binomial theorem formula is
Properties of Binomial Theorem
The number of coefficients in the binomial expansion of (x + y)n is equal to (n + 1).
There are (n+1) terms in the expansion of (x+y)n.
The first and the last terms are xn and yn respectively.
From the beginning of the expansion, the powers of x, decrease from n up to 0, and the powers of a, increase from 0 up to n.
The binomial coefficients in the expansion are arranged in an array, which is called Pascal's triangle. This pattern developed is summed up by the binomial theorem formula.