Coagulating power is inversely proportional to coagulating value, and higher charge density of ions increases coagulating efficiency
The coagulating power of an electrolyte is inversely proportional to its coagulating value:
Coagulating power ∝ \(\frac{1}{\text{Coagulating value}}\)
The ratio of their coagulating powers is given by:
\(\frac{\text{Coagulating power of AlCl}_3}{\text{Coagulating power of NaCl}} = \frac{\text{Coagulating value of NaCl}}{\text{Coagulating value of AlCl}_3}\)
\(\frac{\text{Coagulating power of AlCl}_3}{\text{Coagulating power of NaCl}} = \frac{50.04}{0.09}\)
\(x = \frac{50.04}{0.09} = 556\)
The coagulating power of AlCl3 is 556 times that of NaCl.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are

Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: H2Te is more acidic than H2S.
Reason R: Bond dissociation enthalpy of H2Te is lower than H2S.
In light of the above statements, choose the most appropriate from the options given below:


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)