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The value of \(\lim_{x \to a} \frac{\log x - 1}{x - a}\) is equal to
If \[ f(x) = \begin{cases} \frac{1 - \sin x}{(n - 2x)^2} & \text{if} \quad x \neq \frac{\pi}{2} \log (\sin x) \cdot \log \left( 1 + \frac{\pi}{4x + x^2} \right) & \text{if} \quad x = \frac{\pi}{2} \end{cases} \] is continuous at \( x = \frac{\pi}{2} \), then \( k \) is equal to
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If \( f(x) = [x \sin n\pi x] \), then which of the following is incorrect?
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The limit \[ \lim_{x \to 0} \frac{1 - \cos 2x}{x \tan 4x} \]