Concept:
Sandmeyer's reaction utilizes copper(I) salts ($\text{CuCl}$, $\text{CuBr}$, $\text{CuCN}$) as radical catalysts to replace the diazonium group on an aromatic ring.
Fluorobenzene cannot be synthesized using a standard Sandmeyer procedure because copper(I) fluoride ($\text{CuF}$) is unstable and difficult to prepare, not due to endothermic constraints. Instead, fluorobenzene is synthesized via the Balz-Schiemann reaction by precipitating benzenediazonium fluoroborate ($\text{ArN}_2^+\text{BF}_4^-$) and thermally decomposing it.
Step 1: Evaluate Statement (B).
Statement (B) correctly notes that fluorobenzene cannot be prepared via a standard Sandmeyer reaction, but its explanation regarding highly endothermic constraints is incorrect. The limitation stems from the lack of a viable copper(I) catalyst pathway. Thus, statement (B) is incorrect, making it the targeted selection choice.
Step 2: Verify why the other options are correct statements.
• Statement (A) is correct: Reducing acetoxime ($\text{(CH}_3)_2\text{C}=\text{NOH}$) with sodium and ethanol ($\text{Na/EtOH}$, Bouveault-Blanc reduction conditions) converts the oxime function into a primary amine, yielding propan-2-amine.
• Statement (C) is correct: In an aqueous medium, aliphatic primary amines are more basic than aromatic tertiary or primary amines because resonance delocalizes the lone pair of the nitrogen atom into the benzene ring.
• Statement (D) is correct: Gabriel Phthalimide synthesis relies on an $\text{S}_{\text{N}}2$ displacement of an alkyl halide by the phthalimide anion. Aryl halides do not undergo nucleophilic substitution under standard conditions, meaning aniline cannot be prepared via this pathway.