Chlorobenzene reacts with trichloroacetaldehyde (chloral) in the presence of \(\mathrm{H_2SO_4}\). 
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The Correct Option is C
Solution and Explanation
Protonated chloral is the electrophile; it attacks the para position of one chlorobenzene (Cl is o,p-directing and para is less hindered), and the resulting alcohol loses water to give a second carbocation that attacks the para position of the second chlorobenzene.
The product is \(p,p'\)-dichlorodiphenyltrichloroethane, \(\mathrm{(p\text{-}ClC_6H_4)_2CH{-}CCl_3}\), i.e. DDT, shown in option (3).
Answer: (3) Cl-C6H4-CH(CCl3)-C6H4-Cl
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