Step 1: Analyze the bonding in methyl chloride (CH\(_3\)Cl).
In methyl chloride, the chlorine atom is bonded to a carbon atom that is sp\(^3\) hybridized. The C-Cl bond is a pure single (\(\sigma\)) bond.
Step 2: Analyze the bonding in chlorobenzene (C\(_6\)H\(_5\)Cl).
In chlorobenzene, the chlorine atom is bonded to a carbon atom that is part of the benzene ring. This carbon atom is sp\(^2\) hybridized. Furthermore, the lone pairs of electrons on the chlorine atom can participate in resonance with the \(\pi\)-electron system of the benzene ring.
This resonance delocalization gives the C-Cl bond a
partial double bond character.
Step 3: Compare the bond length and bond strength.
Bond Length:
- A single bond is longer than a double bond.
- The C(sp\(^2\))-Cl bond in chlorobenzene has partial double bond character, making it shorter than the C(sp\(^3\))-Cl single bond in methyl chloride.
- Also, an sp\(^2\) hybrid orbital has more s-character (33.3%) than an sp\(^3\) hybrid orbital (25%). More s-character leads to shorter and stronger bonds.
Therefore, the C-Cl bond in methyl chloride is
longer.
Bond Strength:
- A double bond is stronger than a single bond.
- Because the C-Cl bond in chlorobenzene has partial double bond character, it is stronger than the pure single C-Cl bond in methyl chloride.
Therefore, the C-Cl bond in methyl chloride is
weaker.
Step 4: Final Answer.
Combining the two comparisons, the C-Cl bond in methyl chloride is
longer and weaker than the C-Cl bond in chlorobenzene.