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by application of derivatives approximate value of
Question:
By application of derivatives, approximate value of \[ \sqrt[5]{242} \] is
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For approximation by derivatives, always choose the nearest number whose exact value is easy to compute.
TS EAMCET - 2026
TS EAMCET
Updated On:
Jun 15, 2026
\(2.9085\)
\(2.9975\)
\(2.9527\)
\(2.8529\)
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The Correct Option is
B
Solution and Explanation
Concept:
Approximation formula: \[ f(a+h)\approx f(a)+hf'(a) \] Take function \[ y=x^{1/5} \] Choose nearby perfect power.
Step 1:
Choose nearest value.
\[ 243=3^5 \] Thus \[ 242=243-1 \] Take \[ f(x)=x^{1/5} \]
Step 2:
Find derivative.
\[ f'(x)=\frac15x^{-4/5} \] At \[ x=243 \] \[ f'(243)=\frac1{5(3^4)} = \frac1{405} \]
Step 3:
Apply approximation.
\[ f(242) \approx f(243)-f'(243) \] \[ = 3-\frac1{405} \] \[ = 3-0.002469 \] \[ = 2.99753 \] Hence \[ \boxed{2.9975} \]
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