Boiling of hard water is helpful in removing the temporary hardness by converting calcium hydrogen carbonate and magnesium hydrogen carbonate to
- CaCO3 and Mg(OH)2
- CaCO3 and MgCO3
- Ca(OH)2 and MgCO3
- Ca(OH)2 and Mg(OH)2
The Correct Option is A
Solution and Explanation
The correct answer is (A): CaCO3 and Mg(OH)2
\(Ca(HCO_3)_2\)\(\stackrel{Δ}{→}\) \(CaCO_3\) \(↓\) +\(H_2O\) + \(CO_2\) \(↑\)
\(Mg(HCO_3)_2\)\(\stackrel{Δ }{→}\) \(Mg(OH)_2\)+ \(2CO_2\)\(↑\)
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- Solutions
Concepts Used:
Heavy Water
Heavy water (2H2O, D2O - deuterium oxide) is a form of water that consists only of deuterium rather than the common hydrogen-1 isotope that composes most of the hydrogen in normal water. The presence of the heavier hydrogen isotope gives the water distinct nuclear properties, and the increase of mass gives it slightly distinct physical and chemical properties when compared to normal water.
There are some other heavy forms of water such as;
- Semiheavy water
- Heavy-oxygen water
- Tritiated water
Properties of Hard Water:
- Heavy water is slighter dissociated than light water at a given temperature, and the true concentration of D+ ions is slighter than H+ ions would be for a light water sample at the same temperature.
- Heavy water is more concentrated than ordinary water, and heavy water has physically distinct properties that can be seen without equipment if a frozen sample is dropped into normal water, as it will sink.