Question

Average energy in one time period of a simple harmonic oscillator whose amplitude is A, angular velocity $\omega$ and mass m, is:

• A. $\frac{1}{4} m \omega^2 A^2$
• B. $\frac{1}{2} m \omega^2 A^2$
• C. $m \omega^2 A^2$
• D. $\frac{1}{3} m \omega^2 A^2$

Hint:

In simple harmonic motion, the average energy is proportional to the square of the amplitude and angular velocity.

Answer 1

The Correct Option is B

The average energy in a simple harmonic oscillator is given by: \[ E = \frac{1}{2} m \omega^2 A^2 \] This is the correct expression for the average energy in the system over one full oscillation.