Step 1: Recall the two common temperature scales, Celsius and Fahrenheit, and how the freezing point of water is defined on each.
Step 2: On the Celsius scale, pure water freezes at \(0^\circ C\) and boils at \(100^\circ C\) under normal atmospheric pressure.
Step 3: The conversion formula is \(F = \frac{9}{5}C + 32\). Putting \(C = 0\) gives \(F = 32\).
So pure water freezes at \(32^\circ F\) on the Fahrenheit scale. The correct answer is option B.