
To determine the value of "s" according to Hückel's rule for the given aromatic molecule, follow these steps:
1. **Hückel's Rule**: A molecule is aromatic if it has \(4n+2\) \(\pi\) electrons, where \(n\) is a non-negative integer (0, 1, 2, ...).
2. **Count the \(\pi\) Electrons**: Examine the depicted molecule and identify the double bonds to count the \(\pi\) electrons. There are 14 \(\pi\) electrons in this molecule.
3. **Apply Hückel's Rule**: Set \(4n+2=14\). Solve for \(n\).
\[4n+2=14\]
\[4n=12\]
\[n=3\]
Thus, the value of "s" is 3.
Therefore, according to Hückel's rule, the value of "s" is 3.
| Group I | Group II |
| P) NaCl | 1) Coordination bond |
| Q) $H_2$ | 2) Polar covalent bond |
| R) $Pd-P$ bond in $Pd(PPh_3)_4 | 3) Covalent bond |
| S) $C-Cl$ bond in $CH_3Cl $ | 4) Ionic bond |

