Step 1: Understand the problem setup.
The Earth can be modeled as a sphere. The core is the inner part of the Earth, and the rest of the Earth is made up of the mantle and crust. To solve this, we need to use the formula for the volume of a sphere: \[ V = \frac{4}{3} \pi r^3 \] The core radius is roughly 3,500 km, and the total Earth radius is around 6,371 km. We need to calculate the volume of the core and the total volume of the Earth.
Step 2: Calculate the volume of the Earth and the core.
The total volume of the Earth: \[ V_{\text{Earth}} = \frac{4}{3} \pi (6371)^3 \approx 1.08321 \times 10^{12} \, \text{km}^3 \] The volume of the core: \[ V_{\text{Core}} = \frac{4}{3} \pi (3500)^3 \approx 1.7764 \times 10^{11} \, \text{km}^3 \]
Step 3: Calculate the volume percentage.
The volume percentage of the core relative to the total volume of the Earth is: \[ \text{Volume \% of Core} = \left( \frac{V_{\text{Core}}}{V_{\text{Earth}}} \right) \times 100 = \left( \frac{1.7764 \times 10^{11}}{1.08321 \times 10^{12}} \right) \times 100 \approx 16.4\% \]
Step 4: Conclusion.
The volume percentage of the core relative to the total volume of the Earth is 16.4%.
A magma having density of 2900 kg m\(^-3\) just reaches the surface through a two-layered crust as shown in the figure below. Assuming isostatic equilibrium, its depth of melting is .......... km. (Round off to one decimal place) 
Match the seismic discontinuity in Group I with their occurrence in Earth's interior in Group II.
\[\begin{array}{|l|l|} \hline \textbf{Group I} & \textbf{Group II} \\ \hline \text{P. Conrad} & \text{1. Between lower mantle and outer core} \\ \hline \text{Q. Mohorovičić} & \text{2. Between crust and upper mantle} \\ \hline \text{R. Gutenberg} & \text{3. Between inner and outer core} \\ \hline \text{S. Lehmann} & \text{4. Between lower and upper crust} \\ \hline \end{array}\]
Refer to the schematic sketch given (not to scale). Assume average saturated density of oceanic crustal rocks = 3200 kg/m3, density of ocean water = 1000 kg/m3, and acceleration due to gravity = 10 m/s2. The overburden pressure at a point (P) located 2 km below seabed and 4 km below the ocean surface is ________ MPa. (Answer in integer.) 