The Laplace transform of a sine function is well known:
\[
\mathcal{L}\{\sin(ax)\} = \int_0^\infty e^{-sx} \sin(ax)\, dx
= \frac{a}{s^2 + a^2}, \qquad s>0.
\]
Options (C) and (D) correspond to hyperbolic sine ($\sinh$), and option (B) is the Laplace transform of $\cos(ax)$.
Thus, the correct transform is:
\[
\mathcal{L}\{\sin(ax)\} = \frac{a}{s^2 + a^2}.
\]
Final Answer: $\dfrac{a}{s^2 + a^2}$