To solve the problem of how much of the radioactive element X remains after 100 years, we use the formula for radioactive decay: N(t) = N₀e–λt, where N(t) is the remaining quantity, N₀ is the initial quantity, λ is the decay constant, and t is time in years. First, compute the decay constant λ using the relationship λ = ln 2 / T₁/₂, where T₁/₂ is the half-life of the element.
Substituting known values, T₁/₂ = 30 years, we get:
λ = ln 2 / 30.
Given log 2 = 0.30, hence ln 2 = 2.303 × 0.30 = 0.6909.
Therefore, λ = 0.6909 / 30 ≈ 0.02303 per year.
Next, calculate the remaining quantity after 100 years:
N(100) = 1μg × e–0.02303 × 100 = 1μg × e–2.303.
To find e–2.303, recognize that e–2.303 = 1 / e2.303 = 1 / 10 = 0.1.
Therefore, N(100) = 1μg × 0.1 = 0.1μg.
The amount of X remaining is 1.0 × 10–1 μg, which is within the specified range of the solution, confirming its validity.
\(kt=ln\frac {1}{1−x}\)
\(\frac {0.693}{30}(100)=ln\frac {1}{1−x}\)
\(2.303=2.303\ log\frac {1}{1−x}\)
\(⇒\frac {1}{1−x}=10\)
\(⇒1=10–10X\)
\(⇒X=\frac {9}{10}\)
\(⇒X =0.9\) μg
Amount of X remaining\(=1–X\)
\(=1–0.9\)
\(=0.1\) μg
\(=1×10^{−1}\) μg
So, the answer is \(1\).
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
The atomic structure of an element refers to the constitution of its nucleus and the arrangement of the electrons around it. Primarily, the atomic structure of matter is made up of protons, electrons and neutrons.
Dalton proposed that every matter is composed of atoms that are indivisible and indestructible.
The following are the postulates of his theory:
Several atomic structures of an element can exist, which differ in the total number of nucleons.These variants of elements having a different nucleon number (also known as the mass number) are called isotopes of the element. Therefore, the isotopes of an element have the same number of protons but differ in the number of neutrons. For example, there exist three known naturally occurring isotopes of hydrogen, namely, protium, deuterium, and tritium.