As a result of change in the magnetic flux linked to the closed loop shown in figure, an emf, $V$ volt is induced in the loop. The work done (in joule) in taking a charge $q$ coulomb once along the loop is
Updated On: Jul 6, 2022
$qV$
zero
$2qV$
$\frac{qV}{2}$
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The Correct Option isA
Solution and Explanation
Work done in taking a charge $= Q$
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Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
When we place the conductor in a changing magnetic field.
When the conductor constantly moves in a stationary field.