An organic compound with 51.6% sulfur is heated in a Carius tube. The amount of this compound which will form 0.752 g of barium sulphate is ___________ \( \times \) 10\( - \)1 g.
(Given molar mass of barium sulphate 233 g mol\( - \)1) (Nearest integer).
An organic compound with 51.6% sulfur is heated in a Carius tube. The amount of this compound which will form 0.752 g of barium sulphate is ___________ \( \times \) 10\( - \)1 g.
(Given molar mass of barium sulphate 233 g mol\( - \)1) (Nearest integer).
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Correct Answer: 2
Solution and Explanation
Step 2: This sulfur came from the organic compound which has 51.6% S. Mass of compound \(= \dfrac{0.1033}{0.516} = 0.2002\) g.
Step 3: \(0.2002\ \text{g} \approx 2\times10^{-1}\) g.
Answer: 2
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