

Given reactions:
The compound (A) undergoes these reactions:
\[ \text{H}_2, \, \text{Pt} \rightarrow \text{Saturated compound} \] \[ \text{Hot alk. KMnO}_4 \rightarrow \text{Carboxylation of the methyl group} \] \[ \text{H}^+, \, \text{H}_2\text{O} \rightarrow \text{Carboxylic acid formation} \]
Let's consider the structure of compound (A). The first reaction with hydrogen (\( \text{H}_2 \)) and platinum (\( \text{Pt} \)) suggests that the compound contains a double bond or an unsaturation. Hydrogenation would reduce the unsaturation to a saturated structure. The second reaction with hot alkaline KMnO₄ is a strong oxidizing reaction that cleaves the methyl group (\( -\text{CH}_3 \)) in methylbenzene (toluene) and oxidizes it to a carboxyl group (\( -\text{COOH} \)), forming benzoic acid. The final acidic hydrolysis ensures the formation of carboxylic acid as the final product.
Conclusion: Compound (A) is likely to be toluene (methylbenzene), and after the reactions, the product will be benzoic acid.
Therefore, compound (A) corresponds to: Option 1 (Toluene), and the final product is benzoic acid.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)