An OPAMP is connected in a circuit with a Zener diode as shown in the figure. The value of resistance \( R \) in kΩ for obtaining a regulated output \( V_0 = 9 \, \text{V} \) is: 
Step 1: Understanding the circuit.
In the given circuit, the Zener diode is used to maintain a constant voltage of 4.7 V, and the OPAMP works as a voltage follower. The input voltage \( V_{\text{in}} = 12 \, \text{V} \), and the output voltage \( V_0 \) is regulated to 9 V.
Step 2: Calculate the value of resistance \( R \).
Using the voltage divider formula, the output voltage \( V_0 \) can be written as: \[ V_0 = V_{\text{in}} \times \frac{R}{R + R_z} \] where \( R_z = 1 \, \text{k}\Omega \) is the resistance of the Zener diode. We are given \( V_0 = 9 \, \text{V} \) and \( V_{\text{in}} = 12 \, \text{V} \).
Step 3: Solve for \( R \).
Substitute the known values: \[ 9 = 12 \times \frac{R}{R + 1} \] Solving this equation gives \( R \approx 1.10 \, \text{k}\Omega \), so the value of \( R \) is between 1.05 and 1.15 kΩ.
For the non-inverting amplifier shown in the figure, the input voltage is 1 V. The feedback network consists of 2 k$\Omega$ and 1 k$\Omega$ resistors as shown.
If the switch is open, $V_o = x$.
If the switch is closed, $V_o = ____ x$.

In the given op-amp circuit, the non-inverting terminal is grounded. The input voltage is 2 V applied through 1 k$\Omega$. The feedback resistor is 1 k$\Omega$. The output is connected to a 2 k$\Omega$ load to ground and also through a 2 k$\Omega$ resistor to the op-amp output. Find the output voltage $V_0$ and currents $I_1$, $I_0$, and $I_x$.

In the given circuit, the non-inverting input of the op-amp is at 3 V. The op-amp drives the base of a transistor as shown. The emitter is connected to a 1 k$\Omega$ resistor to ground and the collector is connected to 12 V through a 2 k$\Omega$ resistor. Find the output current $I_o$ supplied by the op-amp.

