Question:

An octahedral complex of \(\mathrm{Co^{3+}}\) is diamagnetic. The hybridisation involved in the formation of the complex is :

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Diamagnetic means no unpaired electrons, so the inner (n-1)d orbitals are used.
Updated On: Nov 11, 2026
  • \(\mathrm{dsp^2}\)
  • \(\mathrm{d^2sp^3}\)
  • \(\mathrm{dsp^3d}\)
  • \(\mathrm{sp^3d^2}\)
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The Correct Option is B

Solution and Explanation

Co (Z = 27) has configuration \(3d^7 4s^2\), so \(\mathrm{Co^{3+}}\) is \(3d^6\).
A diamagnetic complex must have all six d electrons paired, which a strong field ligand achieves by pairing them in three \(3d\) orbitals.
Two \(3d\) orbitals are then empty and, together with one \(4s\) and three \(4p\) orbitals, form six hybrid orbitals: \(\mathrm{d^2sp^3}\) (inner orbital octahedral complex).
Answer: (2) \(\mathrm{d^2sp^3}\)
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