Question:

An n-type and p-type semiconductor can be obtained by respectively doping pure silicon with

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Remember:
- \textbf{n} is for \textbf{n}egative (electron): needs Group 1\textbf{5} (4 + 1 extra).
- \textbf{p} is for \textbf{p}ositive (hole): needs Group 1\textbf{3} (4 - 1 missing).
Updated On: Apr 23, 2026
  • Arsenic and Phosphorous respectively
  • Indium and Aluminium respectively
  • Phosphorous and Indium respectively
  • Aluminium and Boron respectively
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Question:
The question asks to identify the correct pairs of dopant elements required to create n-type and p-type semiconductors from intrinsic silicon.
Step 3: Detailed Explanation:
Silicon is a Group 14 element with 4 valence electrons.
1. n-type semiconductor: Obtained by doping silicon with pentavalent impurities (Group 15 elements) which have 5 valence electrons. Common examples are Phosphorous (P), Arsenic (As), and Antimony (Sb). The fifth electron remains free as a majority charge carrier.
2. p-type semiconductor: Obtained by doping silicon with trivalent impurities (Group 13 elements) which have 3 valence electrons. Common examples are Boron (B), Aluminium (Al), Gallium (Ga), and Indium (In). The deficiency of one electron creates a "hole" as a majority charge carrier.
Evaluating option (3): Phosphorous (Group 15) for n-type and Indium (Group 13) for p-type is a correct match.
Step 4: Final Answer:
Phosphorous and Indium are the respective dopants for n and p-type semiconductors, matching option (3).
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