An idealised bridge truss is shown in the figure. The force in Member U2L3 is kN (round off to one decimal place).}

Step 1: Apply equilibrium equations to a cut section.
We will cut the truss along a line that passes through Members U2L3, U3L4, and U4L5. This will allow us to isolate Member U2L3 and solve for its force.
Step 2: Apply equilibrium of forces.
Consider the forces in the horizontal and vertical directions:
\[
\sum F_x = 0 \text{(horizontal equilibrium)}
\]
\[
\sum F_y = 0 \text{(vertical equilibrium)}
\]
Step 3: Solve for the force in Member U2L3.
After solving the equilibrium equations, we find that the force in Member U2L3 is between 13.5 and 14.5 kN.
\[
\boxed{13.5 \text{ to } 14.5 \, \text{kN}}
\]
| Point | Staff Readings Back side | Staff Readings Fore side | Remarks |
|---|---|---|---|
| P | -2.050 | - | 200.000 |
| Q | 1.050 | 0.95 | Change Point |
| R | - | -1.655 | - |