An empty LPG cylinder weighs 14.8 kg. When full, it weighs 29.0 kg and shows a pressure of 3.47 atm. In the course of use at ambient temperature, the mass of the cylinder is reduced to 23.0 kg. The final pressure inside of the cylinder is _________ atm. (Nearest integer)
(Assume LPG of be an ideal gas)
(Assume LPG of be an ideal gas)
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Correct Answer: 2
Solution and Explanation
Step 2: Mass of LPG after use = 23.0 - 14.8 = 8.2 kg.
Step 3: PV = nRT with V and T constant gives \(P \propto n \propto m\). So \(\dfrac{P_2}{P_1} = \dfrac{8.2}{14.2}\).
Step 4: \(P_2 = 3.47 \times \dfrac{8.2}{14.2} = 2.004\) atm, i.e. 2 atm.
Answer: 2
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