Question:

An electrical appliance rated 1000 W is operated at 250 V. What current does it draw?

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Use \(P = VI\) and solve for \(I\).
Updated On: Nov 3, 2026
  • 0.25 A
  • 2.5 A
  • 4.0 A
  • 10 A
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The Correct Option is C

Solution and Explanation

Step 1: Understand the data:
The appliance is rated 1000 W, so its power is \(P = 1000\) W. It runs at \(V = 250\) V. We need the current \(I\) it draws.

Step 2: Choose the formula:
Electric power is the product of voltage and current:
\[ P = V \times I \]
So the current is \(I = \dfrac{P}{V}\).

Step 3: Substitute the values:
\[ I = \frac{1000}{250} = 4 \text{ A} \]

Step 4: Why the other options are wrong:
Option A (0.25 A) comes from dividing the other way round, \(250/1000 = 0.25\). That is \(V/P\), which is not a current. Option B (2.5 A) and option D (10 A) do not match \(1000/250\). Option D would be right only for a 2500 W appliance at 250 V. Only 4.0 A satisfies \(P = VI\). So option C is correct.

Final Answer:
The appliance draws a current of 4 A, which is option (C). \[ \boxed{I = 4 \text{ A}} \]
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