Question:

An electric dipole with dipole moment \(5\times10^{-7}\ \text{C m}\) is in the electric field of
\[ 2\times10^4\ \text{N C}^{-1} \] at an angle of \(60^\circ\) with the direction of the electric field. The torque acting on the dipole is

Show Hint

The torque on an electric dipole is maximum when the dipole is perpendicular to the electric field, i.e., when \(\theta=90^\circ\).
Updated On: Jun 15, 2026
  • \(9\times10^{-3}\ \text{N m}\)
  • \(1\times10^{-4}\ \text{N m}\)
  • \(8.66\times10^{-3}\ \text{N m}\)
  • \(2.88\times10^{-3}\ \text{N m}\)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Step 1: Use the formula for torque on an electric dipole.
Torque acting on an electric dipole placed in a uniform electric field is given by
\[ \tau=pE\sin\theta \]
where
\[ p=5\times10^{-7}\ \text{C m} \] is the dipole moment,
\[ E=2\times10^4\ \text{N C}^{-1} \] is the electric field strength, and
\[ \theta=60^\circ \] is the angle between dipole moment and electric field.

Step 2: Substitute the given values.
\[ \tau=(5\times10^{-7})(2\times10^4)\sin60^\circ \]
Since
\[ \sin60^\circ=\frac{\sqrt3}{2} \]
\[ \tau=(10\times10^{-3})\times\frac{\sqrt3}{2} \]
\[ \tau=10^{-2}\times0.866 \]
\[ \tau=8.66\times10^{-3}\ \text{N m} \]

Step 3: Final conclusion.
Hence, the torque acting on the dipole is
\[ \boxed{8.66\times10^{-3}\ \text{N m}} \]
Was this answer helpful?
0
0