Component of electric field at point P parallel to $ X- $ axis, $ {{E}_{X}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{2(p\cos \pi /3)}{{{r}^{3}}} $ $ \frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{P}{{{r}^{3}}} $ Component of electric field of point $ P $ perpendicular to $ X- $ axis, $ {{E}_{Y}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{p\sin \pi /3}{{{r}^{3}}} $ $ =\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{\sqrt{3}p}{2{{r}^{3}}} $ $ \therefore $ $ \tan \theta =\frac{{{E}_{Y}}}{{{E}_{X}}}=\frac{\sqrt{3}}{2} $ $ \therefore $ $ \theta ={{\tan }^{-1}}\left( \frac{\sqrt{3}}{2} \right) $