Question

An article A is sold for ₹200 more than selling price of another article 'B'. If 'B' is sold for 5% less than that of 'A' and the cost price of 'B' is ₹2500, then what is the percentage of profit on 'B'?

• A. 51%
• B. 52%
• C. 53%
• D. 54%

Hint:

Profit % = $\frac{\text{Selling Price} - \text{Cost Price}}{\text{Cost Price}} \times 100$.

Answer 1

The Correct Option is B

Step 1: Concept
Profit and Loss calculations.

Step 2: Analysis
Let $S_A$ and $S_B$ be selling prices. $S_A = S_B + 200$.
$S_B = 0.95 \times S_A$.

Step 3: Calculation
$S_B = 0.95(S_B + 200) \implies S_B = 0.95S_B + 190 \implies 0.05S_B = 190 \implies S_B = 3800$.
Profit on B = $3800 - 2500 = 1300$.
Profit % = $\frac{1300}{2500} \times 100 = 52%$.

Step 4: Conclusion
The profit percentage on article B is 52%. Final Answer: (B)