To determine how many of the cations $K^+$, $Li^+$, $Rb^+$, and $Cs^+$ have ionic radii more than $Na^+$, we need to consider their ionic radii. The ionic radii (in pm) for these ions are approximately as follows:
| Cation | Ionic Radius (pm) |
|---|---|
| $Li^+$ | 76 |
| $Na^+$ | 102 |
| $K^+$ | 138 |
| $Rb^+$ | 152 |
| $Cs^+$ | 167 |
Comparing each cation to $Na^+$ (102 pm):
Thus, the number of cations with ionic radii more than $Na^+$ is 3. This value fits within the expected range of 3,3, confirming its correctness.
Therefore, the answer is: 3
| Group I | Group II |
| P) NaCl | 1) Coordination bond |
| Q) $H_2$ | 2) Polar covalent bond |
| R) $Pd-P$ bond in $Pd(PPh_3)_4 | 3) Covalent bond |
| S) $C-Cl$ bond in $CH_3Cl $ | 4) Ionic bond |

