Step 1: Recall the formulae for the area of square and circle.
Let the perimeter of Adu's square land be \( P \). The perimeter of a square is given by \( P = 4 \times \text{side length} \), so the side length of the square is \( \frac{P}{4} \).
The area of the square is \( \text{Area of square} = \left( \frac{P}{4} \right)^2 = \frac{P^2}{16} \).
For Amu's circular land, the perimeter is the circumference, which is given by \( P = 2 \pi r \), where \( r \) is the radius. Thus, \( r = \frac{P}{2\pi} \).
The area of the circle is \( \text{Area of circle} = \pi r^2 = \pi \left( \frac{P}{2\pi} \right)^2 = \frac{P^2}{4\pi} \).
Step 2: Calculate the ratio of areas.
The ratio of the areas of Adu’s square to Amu’s circle is:
\[
\text{Ratio} = \frac{\frac{P^2}{16}}{\frac{P^2}{4\pi}} = \frac{1}{16} \times \frac{4\pi}{1} = \frac{\pi}{4}
\]
Final Answer:
\[
\boxed{\pi^2 : 4}
\]