The reaction is as follows and will produce :
\(BaO_2 \;.\; 8H_2O+H_2SO_4 → BaSO_4+H_2O_2+H_2O\)
Hence, the correct option is (D): \(BaSO_4\) and \(H_2O_2\)

In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 