We can identify the active materials by looking at the overall reversible reaction of a lead-acid cell: \[ \text{Pb} + \text{PbO}_2 + 2\text{H}_2\text{SO}_4 \rightleftharpoons 2\text{PbSO}_4 + 2\text{H}_2\text{O}. \] Every substance appearing on the reactant side that participates directly and gets consumed/transformed during discharge is an "active material." Let's check each option against this reaction.
The discharge reaction shows that spongy lead, lead peroxide, and dilute sulfuric acid are all directly involved as active materials.
Therefore, the correct answer is all of these.