Step 1: Understanding the Concept:
We need to find the time $t$ at which a given function $f(t)$, representing the number of shares, reaches its maximum value. This is a classic optimization problem solvable using the first and second derivative tests.
Step 2: Key Formula or Approach:
1. Find the first derivative $f'(t)$.
2. Set $f'(t) = 0$ to find the critical points (potential maxima or minima).
3. Find the second derivative $f''(t)$.
4. Evaluate $f''(t)$ at the critical points. A negative value indicates a local maximum.
Step 3: Detailed Explanation:
The function for the number of shares is:
\[ f(t) = -2t^3 + 3t^2 + 5 \]
Calculate the first derivative with respect to $t$:
\[ f'(t) = \frac{d}{dt}(-2t^3 + 3t^2 + 5) = -6t^2 + 6t \]
To find critical points, set the first derivative to zero:
\[ -6t^2 + 6t = 0 \]
Factor the equation:
\[ -6t(t - 1) = 0 \]
This gives two critical points:
$t = 0$ and $t = 1$.
Since time $t$ must be meaningful in the context of the problem (usually $t>0$ for something "getting viral" after posting), $t=1$ is our primary candidate. Let's verify it's a maximum.
Calculate the second derivative:
\[ f''(t) = \frac{d}{dt}(-6t^2 + 6t) = -12t + 6 \]
Evaluate the second derivative at the critical points:
At $t = 0$: $f''(0) = -12(0) + 6 = 6>0$. This indicates a local minimum.
At $t = 1$: $f''(1) = -12(1) + 6 = -6<0$. Since the second derivative is negative, the function attains a local maximum at this point.
Therefore, the maximum number of shares occurs at $t = 1$ hour.
Step 4: Final Answer:
The video gets the maximum number of shares at $t = 1$.