Question:

A woman sells to the first customer half her stock and half an apple, to the second customer half her remaining stock and half an apple, and so on to a third and fourth customer. She finds she has 15 apples left. How many apples did she have originally?

Show Hint

For "half plus half" problems, working backward by adding 0.5 and doubling at each step is much faster than setting up a forward equation.
Updated On: Mar 27, 2026
  • 250
  • 255
  • 252
  • 260
  • 270
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation


Step 1: Analyse options.

- Let the total apples be $x$. - After the 1st customer: $x - (\frac{x}{2} + 0.5) = \frac{x-1}{2}$. - This pattern continues for four customers. - Working backward: If she has 15 left after the 4th, before the 4th she had $(15 + 0.5) \times 2 = 31$. - Before the 3rd: $(31 + 0.5) \times 2 = 63$. - Before the 2nd: $(63 + 0.5) \times 2 = 127$. - Before the 1st: $(127 + 0.5) \times 2 = 255$.
Step 2: Conclusion.

The original number of apples was 255. Final Answer: (b) 255
Was this answer helpful?
0
0