Step 1: Understand the information.
- The distance between the two volcanic ash beds is \( 195 \, \text{m} \).
- The age of the volcanic ash bed at the bottom is \( 109 \, \text{Ma} \), and the age of the volcanic ash bed at the top is \( 96 \, \text{Ma} \).
- The fossiliferous limestone bed is \( 65 \, \text{m} \) above the basal volcanic ash bed.
Step 2: Calculate the sedimentation rate.
The age difference between the two volcanic ash beds is:
\[
109 \, \text{Ma} - 96 \, \text{Ma} = 13 \, \text{Ma}
\]
The sedimentation rate is the age difference divided by the distance between the beds:
\[
\text{Sedimentation rate} = \frac{13 \, \text{Ma}}{195 \, \text{m}} = 0.06667 \, \text{Ma/m}
\]
Step 3: Calculate the age of the limestone bed.
Now, calculate the age of the limestone bed, which is \( 65 \, \text{m} \) above the basal volcanic ash bed:
\[
\text{Age of limestone bed} = 96 \, \text{Ma} + \left( 65 \, \text{m} \times 0.06667 \, \text{Ma/m} \right) = 96 \, \text{Ma} + 4.33 \, \text{Ma} = 100.33 \, \text{Ma}
\]
Step 4: Round to the nearest integer.
The age of the fossiliferous limestone bed is approximately:
\[
\boxed{100} \, \text{Ma}
\]