Question:

A value of \(x\) for which \(\sin\left(\cot^{-1}(1+x)\right)=\cos\left(\tan^{-1}x\right)\), is :

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Convert both sides to algebraic expressions using right-triangle ratios.
Updated On: Oct 31, 2026
  • \(-\frac12\)
  • 1
  • 0
  • \(\frac12\)
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The Correct Option is A

Solution and Explanation

If \(\cot\alpha=1+x\) then \(\sin\alpha=\frac{1}{\sqrt{1+(1+x)^2}}\).
If \(\tan\beta=x\) then \(\cos\beta=\frac{1}{\sqrt{1+x^2}}\).
Equating: \(1+(1+x)^2=1+x^2\Rightarrow (1+x)^2=x^2\Rightarrow 1+2x=0\Rightarrow x=-\frac12\).
Answer: (1) \(-\frac12\)
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