For covering 594 km, a truck will be required diesel = 108 liters
∴ For covering 1 km, a truck will be required diesel = \(\frac{108}{594}\)
= \(\frac{2}{11}\)
∴ For covering 1650 km, a truck will be required diesel = \(\frac{2}{11}\)×1650
= 300 liters
Thus, 300 liters diesel will be required by the truck to cover a distance of 1650 km.
Given:
The truck uses 108 liters of diesel to cover 594 km.
First, calculate the diesel consumption rate:
\(\text{Diesel consumption rate} = \frac{108 \, \text{liters}}{594 \, \text{km}}\)
\(\text{Diesel consumption rate} = \frac{108}{594}= \frac{2}{11} \, \text{liters per km}\)
Now, we need to find the amount of diesel required to cover 1650 km:
\(\text{Diesel required} = \text{Diesel consumption rate} \times \text{Distance}\)
\(\text{Diesel required} = \frac{2}{11} \, \text{liters per km} \times 1650 \, \text{km}\)
Calculate the diesel required:
\(\text{Diesel required} = \frac{2 \times 1650}{11}= \frac{3300}{11}\)
\(\text{Diesel required} = 300 \, \text{liters}\)
So, the answer is 300 liters.
Write first five multiples of :
| Column 1 | Column 2 |
| (i) 35 | (a) Multiple of 8 |
| (ii) 15 | (b) Multiple of 7 |
| (iii) 16 | (c) Multiple of 70 |
| (iv) 20 | (d) Factor of 30 |
| (v) 25 | (e) Factor of 50 |
| (f) Factor of 20 |
Cost of 5 kg of wheat is 91.50 Rs.
(a) What will be the cost of 8 kg of wheat?
(b) What quantity of wheat can be purchased in Rs.183?
Write first five multiples of :
| Column 1 | Column 2 |
| (i) 35 | (a) Multiple of 8 |
| (ii) 15 | (b) Multiple of 7 |
| (iii) 16 | (c) Multiple of 70 |
| (iv) 20 | (d) Factor of 30 |
| (v) 25 | (e) Factor of 50 |
| (f) Factor of 20 |