A tree breaks due to a storm and the broken part bends so that the top of the tree touches the ground making an angle $30^\circ$ with it. The distance between the foot of the tree and the point where the top touches the ground is 8 m. Then the height of the tree is:
Show Hint
In broken tree problems, form a right triangle and apply trigonometric ratios.
Concept:
Use right triangle and trigonometry.
Step 1: Let height of broken part = $h$.
The broken part makes $30^\circ$ with the ground.
Step 2: Use cosine.
\[
\cos 30^\circ = \frac{{base}}{{hypotenuse}} = \frac{8}{h}
\]
\[
\frac{\sqrt{3}}{2} = \frac{8}{h}
\Rightarrow h = \frac{16}{\sqrt{3}}
\]
Step 3: Total height.
\[
{Height} = h = \frac{16}{\sqrt{3}} = 8\sqrt{3}
\]
Hence, the height of the tree is $8\sqrt{3$ meters.