Question:
A three-hinged arch of span \(8\,\mathrm{m}\) carries a central point load of \(32\,\mathrm{kN}\). If the central rise is \(2\,\mathrm{m}\), the horizontal thrust is
A three-hinged arch of span \(8\,\mathrm{m}\) carries a central point load of \(32\,\mathrm{kN}\). If the central rise is \(2\,\mathrm{m}\), the horizontal thrust is
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For a three-hinged arch carrying a central point load,
\[
\boxed{H=\frac{WL}{4h}.}
\]
Updated On: Jul 23, 2026
- \(12\,\mathrm{kN}\)
- \(16\,\mathrm{kN}\)
- \(24\,\mathrm{kN}\)
- \(32\,\mathrm{kN}\)
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The Correct Option is D
Solution and Explanation
Step 1: Use the horizontal thrust formula for a three-hinged arch with a central point load.
\[
H=\frac{WL}{4h},
\]
where
\[
W=32\,\mathrm{kN},\qquad
L=8\,\mathrm{m},\qquad
h=2\,\mathrm{m}.
\]
Step 2: Substitute the values. \[ H=\frac{32\times8}{4\times2} =\frac{256}{8} =32\,\mathrm{kN}. \] Hence, \[ \boxed{32\,\mathrm{kN}} \] is the correct answer.
Step 2: Substitute the values. \[ H=\frac{32\times8}{4\times2} =\frac{256}{8} =32\,\mathrm{kN}. \] Hence, \[ \boxed{32\,\mathrm{kN}} \] is the correct answer.
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