Question:

A system does 200 J of work and at the same time absorbs 150 J of heat. The magnitude of the change in internal energy is ____________ J. (Nearest integer)

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Apply the first law, \(\Delta U = q + w\), with work done BY the system taken as negative.
Updated On: Nov 4, 2026
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Correct Answer: 50

Solution and Explanation

Heat absorbed by the system: \(q = +150\) J. Work done by the system: \(w = -200\) J.
\(\Delta U = q + w = 150 - 200 = -50\) J.
The magnitude is 50 J.
Answer: 50
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