Question:
A student needs to enroll for a minimum of 60 credits. A student cannot enroll for
more than 70 credits. The credits are divided amongst project and three distinct
sets of courses namely, core courses, specialization courses, and elective courses.
It is compulsory for a student to enroll for exactly 15 credits of core courses and
exactly 20 credits of project. In addition, a student has to enroll for a minimum of
10 credits of specialization courses. The maximum credits of elective courses that
a student can enroll for is ______
A student needs to enroll for a minimum of 60 credits. A student cannot enroll for
more than 70 credits. The credits are divided amongst project and three distinct
sets of courses namely, core courses, specialization courses, and elective courses.
It is compulsory for a student to enroll for exactly 15 credits of core courses and
exactly 20 credits of project. In addition, a student has to enroll for a minimum of
10 credits of specialization courses. The maximum credits of elective courses that
a student can enroll for is ______
Show Hint
Maximize electives by taking Total credits at its upper limit (70) and specialization credits at its lower limit (10), then subtract the fixed core (15) and project (20) credits.
Updated On: Jul 7, 2026
- 10
- 15
- 20
- 25
Show Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: The total credits a student enrolls for must satisfy \(60 \le \text{Total} \le 70\).
Step 2: Fixed components: core courses = 15 credits (exact) and project = 20 credits (exact), together using \(15+20 = 35\) credits that cannot change.
Step 3: Specialization courses need a minimum of 10 credits. To leave maximum room for electives, take specialization at its minimum, 10 credits, since any extra specialization credit directly reduces the credits available for electives.
Step 4: To maximize electives, use the highest allowed total, i.e., Total = 70.
Step 5: Elective credits = Total − core − project − specialization = \(70 - 15 - 20 - 10 = 25\).
Final Answer: \(\boxed{25}\)
Step 2: Fixed components: core courses = 15 credits (exact) and project = 20 credits (exact), together using \(15+20 = 35\) credits that cannot change.
Step 3: Specialization courses need a minimum of 10 credits. To leave maximum room for electives, take specialization at its minimum, 10 credits, since any extra specialization credit directly reduces the credits available for electives.
Step 4: To maximize electives, use the highest allowed total, i.e., Total = 70.
Step 5: Elective credits = Total − core − project − specialization = \(70 - 15 - 20 - 10 = 25\).
Final Answer: \(\boxed{25}\)
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