Total employees = 3 men + 5 women = 8.
We select 4 employees, with exactly 2 women.
Number of ways to choose 2 women from 5: \(\binom52 = 10\).
Number of ways to choose 2 men from 3: \(\binom32 = 3\).
Thus, number of favorable ways: \(10 \times 3 = 30\).
Total number of ways to choose any 4 employees from 8: \(\binom84 = 70\).
Probability:
\[
P = \frac\textFavorable outcomes\textTotal outcomes = \frac3070 = \frac37
\]
Thus, the probability is \(\frac37\).