Question

A single-phase full bridge voltage source inverter (VSI) feeds a purely inductive load. The inverter output voltage is a square wave in \( 180^\circ \) conduction mode. The fundamental frequency of the output voltage is \( 50 \, \text{Hz} \). If the DC input voltage of the inverter is \( 100 \, \text{V} \) and the value of the load inductance is \( 20 \, \text{mH} \), the peak-to-peak load current in amperes is (rounded off to the nearest integer).

Hint:

For VSI circuits with inductive loads, the peak-to-peak current depends on the fundamental voltage and load reactance.

Answer 1

Correct Answer: 50

Step 1: Calculate the fundamental voltage. The fundamental voltage amplitude is: \[ V_1 = \frac{4 V_{DC}}{\pi}. \] Step 2: Calculate the load current. For a purely inductive load: \[ I_{pp} = \frac{V_1}{\omega L}, \] where \( \omega = 2 \pi f \). Substituting values: \[ I_{pp} = 50 \, \text{A}. \]